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NEET 2020 Solutions Chemistry Questions
1. NEET 2020: The mixture which shows positive deviation from Raoult’s law is:
(1) Benzene + Toluene
(2) Acetone + Chloroform
(3) Chloroethane + Bromoethane
(4) Ethanol + Acetone
Ethanol + Acetone=Extent of Hydrogen Bonding will get reduced because acetone comes in between ethanol molecule
2. NEET 2020: The freezing point of depression constant (Kf) of benzene is 5.12 K kg mol−1. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is (rounded off upto two decimal places) :
1. 0.80 K
2. 0.40 K
3. 0.60 K
4. 0.20 K
ΔTf=Kf×m=5.12×0.078 = 0.40 K
3. NEET 2020: If 8g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapour pressure to 80%, the molar mass (in g mol–1 ) of the solute is [Given that molar mass of n-octane is 114 g mol–1 ]
Relative Lowering of Vapour Pressure
4. NEET 2020: Isotonic solutions have same
(1) vapour pressure
(2) freezing temperature
(3) osmotic pressure
(4) boiling temperature
Isotonic solutions have same osmotic pressure
π1 = C1ST and π2 = C2ST
so at same temp,if C1 = C2 then π1 =π2
Two solutions having the same osmotic pressure across a semipermeable membrane is referred to as an isotonic solution
NEET 2019 Solutions Chemistry Questions
1.NEET 2019: For an ideal solution, the correct option is:
- Δmix G=0 at constant T and P
- Δmix S=0 at constant T and P
- Δmix V≠0 at constant T and P
- Δmix H=0 at constant T and P
For an ideal solution,
ΔHmix=0 ΔGmix<0 ΔSmix>0
2. The mixture that forms maximum boiling azeotrope is:
2. Water+Nitric acid
3. Ethanol +Water
4. Acetone+Carbon disulfide
Water + Nitric Acid forms maximum boiling azeotrope
3. Which of the following statement is correct regarding a solution of two component A and B exhibiting positive deviation from idea behavior?
(1) Intermolecular attractive force between A-A and B-B are stronger than those between A-B
(2) ΔmixH=0 at constant T and P
(3) ΔmixV=0 at constant T and P
(4) Intermolecular attractive forces between A-A and B-B are equal to those between A-B
When inter molecular force is weaker they have higher tendency to get vapourised.
NEET 2018 Solutions Chemistry Questions
NEET 2017 Solutions Chemistry Questions
1. If molality of the dilute solution is doubled, the value of molal depression constant (Kf) will be?
For a dilute solution. the depression in freezing point (ΔTf) is directly proportional to molality (m) of the solution:-
ΔTf ∝ m or ΔTf=Kfm
Where, Kf is called molal depression constant or freezing point depression constant or cryoscopic constant.The value of Kf ,depends only on nature of the solvent and independent of composition of solute particles, i.e. does not depend on the concentration of solution.
2. Which of the following is dependent on temperature?
(3) Mole fraction
(4) Weight percentage
Molarity and normality are temperature dependent because they involve volume of solutions.Volume is dependent on temperature.
Molarity(M)=Moles of solute/ Volume of solution (in L)
Molality,mole fraction and weight percentage do not depend on temperature because they involve masses of solute and solvent.
NEET 2016 Solutions Chemistry Questions
Consider the following liquid-vapour equilibrium
1.The van’t Hoff factor [i] for a dilute aqueous solution of the strong electrolyte barium hydroxide is?
Key idea Strong electrolytes dissociate completely in their solutions.
Van’t Hoff factor=Total number of ions after dissociation
So,for Ba(OH)2 ⇌ Ba2+(aq) + 2OH–(aq)
Number of ions 1 + 2
Van’t Hoff factor, i=1+2=3
2. Which of the following statements about the composition of the vapour over an ideal 1:1 molar mixture of benzene and toluene is correct? Assume that the temperature is constant at 25°C. Given, vapour pressure data at 25°C, benzene = 12.8 kPa, toluene = 3.85 kPa)
1. The vapour will contain a higher percentage of toluene
2. The vapour will contain equal amounts of benzene and toluene
3. Not enough information is given to make a prediction
4. The vapour will contain a higher percentage of benzene
Since, component having higher vapour pressure will have higher percentage in vapour phase. Benzene has vapour pressure 12.8 kPa which is greater than toluene 3.85 kPa.
Therefore, the vapour will contain a higher percentage of benzene.
3. At 100°C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be
4. Which one of the following is incorrect for ideal solution ?
(3) ΔP=P(obs)−P(calculated) by Raoul’s law = 0
NEET 2015 Solutions Chemistry Questions
1. Which one is not equal to zero for an ideal solution?
For an ideal solution:-
(i)There will be no change in volume on mixing the two components i.e. ΔVmixing = 0.
(ii)There will be no change in volume on ΔHmixing = 0. So, ΔSmix≠0 for an ideal solution.
2. Which one of the following elctrolytes has the same value of van’t Hoff’s factor(i) as that of Al2(SO4)3 (if all are 100% ionised)?
3. The boiling point of 0.2 mol kg-1 solution of X in water is greater than equimolal solution of Y in water. Which one of the following statements is true in this case?
1. X is undergoing dissociation in water.
2. Molecular mass of X is greater than the molecular mass of Y.
3. Molecular mass of X is less he molecular mass of y.
4. Y is undergoing dissociation in water while X undergoes no change.
4. Of the following 0.10 m aqueous solutions, which one will exhibit the largest freezing point depression?
NEET 2014 Solutions Chemistry Questions
1. Of the following 0.10 m aqueous solutions, which one will exhibit the largest freezing point depression?
NEET 2013 Solutions Chemistry Questions
1. At 25° C molar conductance of 0.1 molar aqueous solution of ammonium hydroxide is 9.54 ohm-1cm2mol-1 and at infinite dilution its molar conductance is 238 ohm-1cm2mol-1 . The degree of ionisation of ammonium hydroxide at the same concentration and temperature is
NEET 2012 Solutions Chemistry Questions
1. pA and pB are the vapour pressure of pure liquid components, A and B, respectively of an ideal binary solution.If x, represents the mole fraction of component A, the total pressure of the solution will be.
NEET 2011 and old Solutions Chemistry Questions
NEET 2021: The freezing point depression constant format is -1.86°C m-1. If 5.00g Na2SO4 dissolved in 45.0 g H2O, the freezing point is changed by -3.82°C. Calculate the van’t Hoff factor for Na2SO4
NEET 2007: 0.5 molal aqueous solution of a weak acid (HX) is 20% ionised. If Kf for water is 1.86 K kg mol-1, the lowering in freezing point of the solution is:
(1) -1.12 K
(2) 0.56 K
(3) 1.12 K
(4) – 0.56 K
Answer: = 1.2 x 1.86K kg mol-1 x 0.5 = 1.116 K
NEET 2006: A solution containing 10 g per dm3 of urea (molecular mass = 60 g mol-1) is isotonic with a 5% solution of a non-volatile solute. The molecular mass of this non-volatile solute is:
- (1) 250 g mol-1
- (2) 300 g mol-1
- (3) 350 g mol-1
- (4) 200 g mol-1
NEET 2006: 1.00 g of a non-electrolyte solute (molar mass 250g mol) was dissolved in 51.2 g of benzene. If the freezing point depression constant, Kf of benzene is 5.12 K kg mol-1, the freezing point of benzene will be lowered by:-
- (1) 0.4 K
- (2) 0.3 K
- (3) 0.5 K
- (4) 0.2 K
Answer: Molality of non-electrolyte solute = weight of solute in gram/molecular weight of solute/weight of solvent in kg = 1/250/0.0512 = 1/250×0.0512 = 0.0781 m
𐤃Tf = Kf x molality of solution = 5.12×0.0781 = 0.4K
NEET 2006: A solution of acetone in ethanol:
- (1) shows a negative deviation from Raoult’s law
- (2) shows a positive deviation from Raoult’s law
- (3) behaves like a near ideal solution
- (4) obeys Raoult’s law
Answer: (b) A solution of acetone in ethanol shows a positive deviation from Raoult’s law due to miscibility of these two liquids with difference of polarity and length of hydrocarbon chain. 1. Due to the break of H bond between the molecule of ethanol. 2. The components include can escape easily due to high vapour pressure.
NEET 2006: During osmosis, flow of water through a semi-permeable membrane is :
(1) from solution having higher concentration only
(2) from both sides of semi-permeable membrane with equal flow rates
(3) from both sides of semi-permeable membrane with unequal flow rates
(4) from solution having lower concentration only
Answer: from both sides of semi-permeable membrane with unequal flow rates
NEET 2006: A solution containing 10g per dm3 of urea (molecular mass = 60g mol-1) is isotonic with a 5% solution of a non-volatile solute. The molecular mass of this non-volatile solute is :
- 1. 25g mol-1.
- 2. 300g mol-1.
- 3. 350g mol-1.
- 4. 200g mol-1.
NEET 2020 to 1991
NEET UG Previous Year Chemistry Question Papers with Answer of Chemistry Chapter 02 Solutions MCQs available in Pdf for free download. The MCQ Questions for NEET Chemistry with answers have been prepared as per the latest 2021 NEET Chemistry syllabus, books and examination pattern. Multiple Choice Questions form important part of competitive exams and NEET exam and if practiced properly can help you to get higher rank. Refer to more topic wise NEET Chemistry Questions and also download more latest study material for all subjects and do free NEET Chemistry Mock Test
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